"Determine the specific heat of a material if a 30.1 g sample absorbed 47.8 J as it was heated from 293 K to 321 K. Answer in units
of J / g * K."
I tried to do this using Q=mcT, or c=Q/(mT), where Q is heat, m is mass, c is specific heat and T is change in temperature. In the end, I got 47.8J/(30.1g*28K)=.0567, but apparently, this answer is incorrect
.