Okay, one of the problems that I was given was to look at the H1-NMR, C-13-NMR, IR, and MS data and determine the structure as well as IUPAC name. We are given the molecular formula. For the particular problem that I'm looking at, I'm having trouble deciphering the H1-NMR data. Some of it, I do understand. Some of it, I don't. It's basically as follows:
3H ---> triplet
6H -----> doublet
3H -----> doublet
2H -----> triplet
2H -----> multiplet
1H ------> multiplet
1H ------> multiplet
Here's what I've concluded so far. Based on the molecular formula, C8H18, which, to me, looks like octane, along with the IR Spec. data, this is only composed of carbons and hydrogens. It doesn't even have double bonds, from what I can tell anyway.
I know that C-13 NMR doesn't split but H-NMR does. And it splits by the N + 1 rule, n equals the number of bydrogens on the adjacent carbon. So, for example, if something is a quartet, the adjacent carbon has three hydrogens (n + 1= 3 +1 = 4).
Now, what's confusing me about the problem is the fact that there is one with 6 hydrogens, especially given that carbon can only bond to four different atoms.
Could someone please help me?
Thanks.