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Topic: Acetone reaction scheme  (Read 30007 times)

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Offline Dan

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Re: Acetone reaction scheme
« Reply #15 on: February 11, 2013, 11:17:54 AM »
Not a bad idea - the [2+2] cycloaddition looks like a good idea.

Problem is that KOH won't eliminate that alcohol - generally you need acid, but there are exceptions where an E1cb mechanism can operate (e.g. aldol condensation). The KOH will probably hydrolyse the nitrile to the carboxylate. The acid step might do the elimination you are looking for, though you might get a cationic rearrangement of the cyclobutane ring.

To simplify things, I would suggest a [2+2] cycloaddition of propadiene to acrylonitrile to give:

C=C1CC(C#N)C1
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Offline Rutherford

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Re: Acetone reaction scheme
« Reply #16 on: February 11, 2013, 12:14:25 PM »
Yes, K is a hydrocarbon, so your proposition seems correct. KOH is used for converting -CN to -COO- and H3O+ is used to protonate the carboxylate anion. Thanks very much for the help.


I thought that I could do the rest alone, but I got stuck again, there are things I need to learn and I hope that I will do now. The new scheme is attached.
In the first step the keto group and the two carboxylate groups should be reduced, so I got a triol. What happens when TsCl in pyridine is added? That reaction blocks me.

Offline discodermolide

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Re: Acetone reaction scheme
« Reply #17 on: February 11, 2013, 12:36:07 PM »
TSCl/Py forms the para-toluenesulphonate ester of alcohols.
The tosylate thus formed is a good leaving group when attacked by nucleophiles.
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Offline Rutherford

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Re: Acetone reaction scheme
« Reply #18 on: February 11, 2013, 12:51:25 PM »
I don't understand what will be the final product. A triol is made in the first step, so which -OH group takes part in the esterification?

Offline discodermolide

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Re: Acetone reaction scheme
« Reply #19 on: February 11, 2013, 01:08:08 PM »
Probably only the primary ones, but as no quantities of reagents are given I might assume all of them are tosylated?


By the way I am finding this thread very confusing! ???
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Offline Rutherford

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Re: Acetone reaction scheme
« Reply #20 on: February 11, 2013, 02:03:40 PM »
Sorry, these are all parts from the same problem, so I thought to post them in the same topic. It was probably a bad idea. For the next scheme I will open a new topic.

I will continue with this one tomorrow. Thanks till now for the help.

Offline Dan

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Re: Acetone reaction scheme
« Reply #21 on: February 11, 2013, 03:34:19 PM »
Yes, K is a hydrocarbon, so your proposition seems correct.

It would help if you share these additional bits of information from the beginning, do you have any other such hints?

I thought I had it up to U, but I can't see what the hydroxylamine will do, so maybe not...
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Offline Rutherford

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Re: Acetone reaction scheme
« Reply #22 on: February 12, 2013, 09:55:48 AM »
There is no additional info for this scheme and I can't get further than Q  :-\.

Offline discodermolide

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Re: Acetone reaction scheme
« Reply #23 on: February 12, 2013, 10:00:03 AM »
I said this already, R are the tosylates, two primary and one secondary.
Tosylates, which are good leaving groups. They then react with the malonate ester, presumably under basic conditions. So look at that and see where you get.
tri tosylate
CC1=CC=C(S(OC2CC(COS(C3=CC=C(C)C=C3)(=O)=O)(COS(C4=CC=C(C)C=C4)(=O)=O)C2)(=O)=O)C=C1
di tosylate(s)
OC1CC(COS(C2=CC=C(C)C=C2)(=O)=O)(COS(C3=CC=C(C)C=C3)(=O)=O)C1 and OCC1(COS(C2=CC=C(C)C=C2)(=O)=O)CC(OS(C3=CC=C(C)C=C3)(=O)=O)C1

mono tosylate
OC1CC(COS(C2=CC=C(C)C=C2)(=O)=O)(CO)C1

or less likely
OCC1(CO)CC(OS(C2=CC=C(C)C=C2)(=O)=O)C1
« Last Edit: February 12, 2013, 10:10:09 AM by discodermolide »
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Offline Rutherford

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Re: Acetone reaction scheme
« Reply #24 on: February 12, 2013, 10:12:57 AM »
I assumed that the keto group didn't get reduced, so I ended with V being the compound attached. What happens then in the last reactions, if the compound is acceptable?

Offline discodermolide

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Re: Acetone reaction scheme
« Reply #25 on: February 12, 2013, 10:19:06 AM »
Why should the ketone not be reduced by LAH?

OK let's assume it didn't, that is not a reasonable product. The step that is false is T :rarrow:U.
In this case T is this compound O=C1CC2(CC(C(O)=O)C2)C1
So how does an acid react with SOCl2 then NaN3, heat in the presence of tButanol, a named reaction by the way.
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Offline Rutherford

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Re: Acetone reaction scheme
« Reply #26 on: February 12, 2013, 10:25:30 AM »
I thought that an acyl chloride was made, afterwards I didn't know ::). What is the role of the azide and tbutanol?

Offline discodermolide

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Re: Acetone reaction scheme
« Reply #27 on: February 12, 2013, 10:26:57 AM »
Right you get an acid chloride. NaN3 acts as a nucleophile and does what? Don't forget the heat.
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Offline Rutherford

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Re: Acetone reaction scheme
« Reply #28 on: February 12, 2013, 10:55:09 AM »
Substitution so I got the chlorine replaced by azide ion. Don't know what happens then.

Offline discodermolide

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Re: Acetone reaction scheme
« Reply #29 on: February 12, 2013, 11:00:36 AM »
OK, it's a Curtius rearrangement. See the picture. So now we know U (The compounds in brackets are not isolated).
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