Thanks for the replies.
It is Cr(NH3)xCly(OH)z
Again, from the proportion 14x:M=28.75:100, M=48.696x g/mol.
Now, NH3 makes a difference. If x=5, M=243.5g/mol, this would mean 1 or 3 chlorine atoms. As Cr has the charge 3+, I need 3 negative ions, so y+z=3. The mass without chromine and amino groups is 106.5 which corresponds to 3 chlorine atoms, so the formula is [Cr(NH3)5Cl]Cl2. Is this good?