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Topic: Cr(III) amine complex  (Read 9117 times)

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Offline Rutherford

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Re: Cr(III) amine complex
« Reply #15 on: February 25, 2013, 12:44:21 PM »
If no oxygen, chromium will remain in +2 oxidation state.
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Offline XGen

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Re: Cr(III) amine complex
« Reply #16 on: February 25, 2013, 10:07:12 PM »
Doesn't it start and end in the 2+ state?
Cr[(NH3)5Cl]Cl2
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Offline Borek

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Re: Cr(III) amine complex
« Reply #17 on: February 26, 2013, 04:28:37 AM »
Quote from: XGen on February 25, 2013, 10:07:12 PM
Doesn't it start and end in the 2+ state?
Cr[(NH3)5Cl]Cl2

This is Cr3+.
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Offline Radu

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Re: Cr(III) amine complex
« Reply #18 on: April 17, 2013, 10:54:31 AM »
I don't think it's got anything to do with oxygen. I mean a complex that stands for that nitrogen percentage is
[Cr(NH3)5Cl]2Cl(I haven't found another one yet) . The redox equation occurs with transforming the oxygen into water, and Cr2+ into Cr3+. The hydrogen comes from the ammonium chloride.  Thus, the balanced equation may be:
   4 CrCl2 + 16 NH3 + 4 NH4Cl + O2---------- 4 [Cr(NH3)5Cl]2Cl + 2H2O.
 
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Offline Rutherford

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Re: Cr(III) amine complex
« Reply #19 on: April 17, 2013, 12:39:33 PM »
Now, if we remove the oxygen, there won't be a redox reaction happening, so I don't quite understand what you meant by:
Quote
I don't think it's got anything to do with oxygen.
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