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What is the compound at under the scheme?
Well you missed out a complete ring.OK the CH2 protons next to the ketone, one is removed by NaOH to give what?
You mean this structure?Why is this "stable" and what will it attack?
Yes, both statements are OK. Now if it attacks the aldehyde carbonyl what product do you get?
Yes, That's ok, one thing it would be worth showing the resonance structures of the anion.However, there is still one more step to go, what is it?