Corribus, thanks for your reply
This is what I found from the internet :
"In most reactions with sodium borohydride, the aldehyde or ketone is dissolved in the reaction solvent and
a solution of sodium borohydride is added, with external cooling if necessary, at a rate slow enough to keep
the reaction temperature below 25°C. Higher temperatures may decompose the hydride, and adding the
carbonyl compound to the alkaline sodium borohydride solution may cause side reactions of base-sensitive
substrates. The amount of solvent is not crucial, but enough should be used to completely dissolve the
reactants"
Although there is no carbonyl compound involved in my case, could the high temperature decomposition of the hydride which might cause side reactions of base-sensitive substrates be the answer to my question?
As usual, all opinions are welcomed! thanks!