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Topic: Partially methylated disilane  (Read 2142 times)

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Offline Rutherford

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Partially methylated disilane
« on: March 21, 2013, 01:37:42 PM »
From 20 mg of partially methylated disilane, Si2H6-x(CH3)x, 27.8 cm3 of hydrogen are evolved during alkaline hydrolysis at 294 K and 97400 Pa. Calculate the degree of substitution x of the methylated disilane. Only Si-H and Si-Si bonds break.

I know to solve this, except one thing, the reaction. For example, the cleavage of the Si-H bond, I thought is:
Si-H+OH- :rarrow: Si-OH+1/2H2
while it actually is:
Si-H+H2O :rarrow: Si-OH+H2
How could I known that it is the second reaction and not the first, when they said that it is an alkaline hydrolysis, so I expected OH- ions to participate? Where is the logic behind this?

Offline Borek

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Re: Partially methylated disilane
« Reply #1 on: March 21, 2013, 03:10:52 PM »
Si-H+OH- :rarrow: Si-OH+1/2H2

It can't be right for a very simple reason.
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Offline Rutherford

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Re: Partially methylated disilane
« Reply #2 on: March 21, 2013, 03:41:49 PM »
 ::) The charges can't be balanced. I just couldn't notice it. Thanks.

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