J constant is 6 and it is the same as that between 1569 and 1563.I think they are mutual and they may form two doublets.
Doublets have a 1:1 pattern. The peaks you refer to do not, which suggests that they do not form a doublet.
You have 12 peaks, this narrows down your options. Factorise it:
12 = 2 x 2 x 3 (ddt, dtd or tdd)
12 = 3 x 4 (tq or qt)
12 = 2 x 6 (dsext or sextd)
So there are 7 possible ways of generating 12 peaks in the signal.
Look for tell-tale intensity patterns associated with the different individual splitting patterns.
d - 1:1
t - 1:2:1
q - 1:3:3:1
etc...
Can you spot anything that looks like a doublet, triplet, quartet etc. that allows you to narrow down the possible solutions?