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Topic: How do I go about this synthesis?  (Read 1722 times)

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Offline johnj321

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How do I go about this synthesis?
« on: April 15, 2013, 10:34:03 PM »
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« Last Edit: April 16, 2013, 12:08:08 AM by johnj321 »

Offline orgopete

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Re: How do I go about this synthesis?
« Reply #1 on: April 15, 2013, 11:16:59 PM »
If the acetate ester were treated with methoxide, what would happen?
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Offline johnj321

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Re: How do I go about this synthesis?
« Reply #2 on: April 15, 2013, 11:28:59 PM »
Would the methoxide attack both of the electrophilic carbons? I still dont see how that would replace the ester group on the end with an OH

Offline Mitch

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Re: How do I go about this synthesis?
« Reply #3 on: April 16, 2013, 12:02:17 AM »
The product is symmetric, how much of the methoxide would you have to react to get to the product?
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Offline johnj321

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Re: How do I go about this synthesis?
« Reply #4 on: April 16, 2013, 12:02:57 AM »
I figured it out, thank you for responses.

Offline Mitch

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Re: How do I go about this synthesis?
« Reply #5 on: April 16, 2013, 12:09:37 AM »
please don't delete your questions. Many people will use your question to learn from.
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Offline orgopete

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Re: How do I go about this synthesis?
« Reply #6 on: April 16, 2013, 01:43:12 PM »
The starting material was not symmetric, it was CH3OOCCH2CH2CH2OOCCH3, the acetate of methyl 4-hydroxybutanoate. Methoxide would attack each carbonyl. Loss of methoxide from the methyl ester will return a methyl ester. Attack of the acetate carbonyl would give methoxide or the alkoxide of the desired product. With a large amount of alcohol, methoxide would give the desired product through ester exchange.
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