What mass of Na
3PO
4 would you add to 80.0 mL of 0.200 M HCl to obtain a buffer with a pH of 7.75?
Okay so Na
3PO
4 will dissociate in solution and PO
43- will react with H
3O
+.
0.016 moles H
3O
+ will form and react with H
2O.
PO
43- + H
3O
+ HPO
42- + H
2O
HPO
42- reacts with water, and forms H
2PO
42- and OH
-.
HPO
42- + H
2O
H
2PO
41- + OH
-Since this is a buffer, henderson hasselbach can be used. for the pKa, I am unsure what to use. If I use HPO
42- pKa I get a value for the mass of phosphate that is waay off.
I called x/94.97 the moles for phosphate, and 0.016 mol of hydronium. 0.016mols of weak acid HPO
42- will form. From here I put these into HH equation, but I get 6.788g for phosphate, while the answer says much less for Na
3PO
4.
I thought i understood all the reactions taking place, but apparently not.