[Nautis]

I'm given the following:

Na2SO4+Pb(NO3)2 = Pb(SO4)+NaNO3

Blanced = 1Na2SO4+1Pb(NO3)2 = 1Pb(SO4)+2NaNO3

From this, I must create a .1M of each solution.  I am given a liquid Na2SO4, and solid Pb(NO3)2.
How would I go about doing this?

No more than 25ml of each solution can be created either.
 
What is the theoretical mass of the products?

[UG]

Were you really given liquid Na₂SO₄? I think it was a more concentrated solution, do you know its concentration? Anyway, say you had 25 mL of a 0.1 M Pb(NO₃)₂ solution, how many moles of Pb(NO₃)₂ is in solution? Once you have calculated this, you can find the mass of Pb(NO₃)₂ needed

[Nautis]

Thanks for replying

It was labeled "Sodium Sulfate 1M"
And i think i may have worded my sentences wrong in the last post.

We were given solid Lead II Nitrate, and a Liquid sodium sulfate labeled "Sodium Sulfate 1M".

We weren't allowed to make more than a 25ml solution for each.

We were to find out how much of each compound would be needed to make a 25ml solution of each.

 

[UG]

Ok, that's good I'm glad that issue is sorted. So then, in reference to my previous post, do you know how to calculate the number of moles of Pb(NO₃)₂ in 25 mL of a 0.10 M solution? What formulas have you been taught?