[jackal67347]

I am trying to calculate the volume of liquid water i need to place in a sealed container in order to obtain 10 psi of steam pressure in that closed container.  I am trying to steam some catalyst.

Here are the numbers:

Temp: 816 C
Volume of steel pipe: 154.497 ml
Final pressure: 10 psi

If I left out a required number please let me know.

If you could show how you solved it or what equation you're using that' be great.

Thanks in advance to whoever helps me out!

Here is my attempt:

pv=nrt

(.6805 atm)(v)=( .05555 moles h2o)( .08206) (1089.15 K)

7.296 Liters of steam required

So from the steam table I looked at .001003217 specific volume of h2o at room temp
49.526 specific volume of steam at 800C

49526 ratio

so i need .147 ml of water according to this calculation

[Borek]

(.6805 atm)(v)=( .05555 moles h2o)( .08206) (1089.15 K)

No idea what you did here. You are not looking for V (which is given), you are looking for the number of moles.