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Offline BARAJAN

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calculation
« on: May 26, 2013, 06:54:43 AM »
hi guys
I want to calculate the volume of 8.3 mmol NH2OH (50% aqueous solution) with density of 1.11 gr/Lit, I have calculated the volume as mentioned below am I right?  :P
M*8.3 mmol= 274.149 gr
d=M/V---> V=M/d--> V=24.698 μL
thanks for your help

Offline Borek

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Re: calculation
« Reply #1 on: May 26, 2013, 08:32:07 AM »
Regardless of what M is, it is not OK.

So, what M is?
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Offline BARAJAN

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Re: calculation
« Reply #2 on: May 27, 2013, 02:04:36 PM »
Regardless of what M is, it is not OK.

So, what M is?
I meant yhe following equation

density=mass/volume
so M is mass

Offline Borek

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Re: calculation
« Reply #3 on: May 27, 2013, 04:01:36 PM »
If M is mass, what is this meant to mean:

M*8.3 mmol= 274.149 gr
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Offline BARAJAN

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Re: calculation
« Reply #4 on: May 28, 2013, 03:06:55 AM »
If M is mass, what is this meant to mean:

M*8.3 mmol= 274.149 gr
thank you dear Borek for your kindly attention :D
sorry may be this is because of my week language skill, in the mentioned equation I replaced 33.03 (the molar mass of NH2OH) and I multiplied to 8.3 (my desired moles of NH2OH) and I assumed that I need 274.149 gr of NH2OH as the density of 50% aques solution of NH2OH was 1.11 gr/Lit I replaced the calculated mass 274.149 and the density 1.11 in the d=M/V and V= 24 Lit

Offline Borek

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Re: calculation
« Reply #5 on: May 28, 2013, 03:49:53 AM »
So M means whatever you want it at a given moment. Don't be surprised you are confusing yourself and others, when you use the same symbol for different things in a single, short post.

8.3 is not a number of moles, but number of millimoles.
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