[Borek]

What is the density of the sulfuric acid solution (g/mL) if its percent w/w concentration is 60.16% and w/v percent concentration is 90.24%?

[Schrödinger]

bar cbvag svir g/mL?

[curiouscat]

[tex]
\LARGE{\sqrt[3]{3.375}}
[/tex]

g/ml

[Borek]

Have you used density tables?

[Rutherford]

I didn't.
ω(mass share)=m_H2SO4/m_solution=0.6016
φ(volume share)=V_H2SO4/V_solution=0.9024
Dividing:
ω/φ=V_solution/m_solution=0.6667
V_solution=0.6667m_solution
ρ_solution=m_solution/V_solution=m_solution/0.6667m_solution=1.5gcm^-3

[curiouscat]

Have you used density tables?

Nope.

[Schrödinger]

Have you used density tables?

:O No!

It's a fairly simple question. If 100 g of the soln contains 60.16 g of H₂SO₄ and 100 mL of the solution contains 90.24 g of H₂SO₄, all one needs to find out is how many mL of soln corresponds to 60.16 g H₂SO₄, because this volume of soln which corresponds to 60.16 g of H₂SO₄, also weighs 100 g (given).

[Borek]

I know you don't have to. I was wondering how to word the question - whether to name the compound or not. If it is named, it suggests it is a specific case, not a general thing.

[Big-Daddy]

What's the justification for V[H2SO4]/m[H2SO4]=1?

Only then ρ[Solution]=Volume Share/Mass Share=1.500 g/cm³. Otherwise Volume Share/Mass Share=ρ[Solution]*V[H2SO4]/m[H2SO4].

[curiouscat]

What's the justification for V[H2SO4]/m[H2SO4]=1?

Only then ρ[Solution]=Volume Share/Mass Share=1.500 g/cm³. Otherwise Volume Share/Mass Share=ρ[Solution]*V[H2SO4]/m[H2SO4].

density of solution is always equal to mass / volume.

The rest of what you wrote didn't make any sense to me. Especially not what "share" applies to.

Your equations don't even make dimensional sense.

[Big-Daddy]

The rest of what you wrote didn't make any sense to me. Especially not what "share" applies to.

I was looking at Raderford's derivation as it is the only one on the page.

ω(mass share)=m_H2SO4/m_solution=0.6016
φ(volume share)=V_H2SO4/V_solution=0.9024

So there are the definitions of Mass Share and Volume Share.

Dividing:
ω/φ=V_solution/m_solution=0.6667

Look at the expressions for ω and φ; clearly ω/φ=m_H2SO4·V_solution/(m_solution·V_H2SO4). Only if m_H2SO4/V_H2SO4=1 does this reduce to ω/φ=V_solution/m_solution. What's the justification for that?

[curiouscat]

He has a Typo. V should be m.

[Big-Daddy]

He has a Typo. V should be m.

Ah I see. w/v. It's not volume fraction we want but mass concentration, so p[H2SO4]=m[H2SO4]/V[solution]. Got it now, thanks for the help.