[Osh]

From this information im supposed to be able to work out the amount of sulhuric acid im supposed to use in cm^-3 and the mass of magnesium carbonate im supposed to react it with.

Aqueous sulphuric acid; Concentration:10 mol dm^-3.
Solid magnesium carbonate.

[rcflyingboy]

You know its 10 moles per dm cubed. Since 1 cubic centimeter is equal to 1 milliliter convert your units and you should have what you need for the problem.

[Borek]

What process are you referring to? To be able to calculate anything you have to start from the reaction equation.

[Donaldson Tan]

MgCO₃ (s) + H₂SO₄ (aq) => MgSO₄ (aq) + CO₂ (g) + H₂O (l)

let mass of H2SO4 used be M (in unit of grams)
molar mass of H2SO4 = 98.1g/mol
from equation, stoichometric ratio between sulphuric acid and magnesium carbonate is 1:1, so minimum number of mole of sulphur acid needed to react with all the magnesium carbonate is given as M/98.1

minimum volume of sulphuric acid needed
= ( M/98.1 ) / Concentration
= ( M/98.1 ) / 10
= M/981

[Osh]

does that mean i need to calculate what 10moles of magnesium carbonate in grams?

[Donaldson Tan]

minimum volume of sulphuric acid needed
= ( M/98.1 ) / Concentration
= ( M/98.1 ) / 10
= M/981

M/98.1 is the number of moles of the magnesium carbonate, so you just gotta replace M/98.1 with 10moles

min. volume of sulphuric acid = 10/10 = 1dm3