With Sodium you only have to worry about the atomic mass of sodium which is 23.
You will need to work out which reactant (Na or EtOH) is in excess
I found that C
2H
5OH is in excess, so Na is the limiting reagent. Therefore, n(H
2) =0.1mol and V= n*Vm=0.1*22.4=2.24dm
3, Thank you a lot