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Topic: How to get anhydrous HAuCl4?  (Read 11479 times)

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Ling Yug

  • Guest
How to get anhydrous HAuCl4?
« on: February 17, 2006, 06:34:24 PM »
I will prepare Gold nanoparticles by reflux Chloroauric acid, HAuCl4 in toluene and oleylamine. Now, I ordered chemical HAuCl4.3H2O already but I wonder that do I need to remove H2O from HAuCl43H2O before do the reaction? If I should do, could you please tell me how to get an anhydrous from of HAuCl4.3H2O ???
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shelanachium

  • Guest
Re:How to get anhydrous HAuCl4?
« Reply #1 on: February 19, 2006, 04:18:03 PM »
I think you may find it impossible to obtain HAuCl4 anhydrous. The hydrate is in fact a salt of H3O+ as are the 'hydrates' of other very strong acids like HClO4. But whilst HClO4 exists as an anhydrous compound, HAuCl4 will give HCl + AuCl3, just as the similar HBF4 cannot be obtained anhydrous and attempts to do so yield HF + BF3. However AuCl3 may be what you want anyway - it is possible SOCl2 might do the trick, or if this is too reducing, COCl2 - both are used regularly to obtain anhydrous chlorides, e.g.

AlCl3.6H2O + 3COCl2 -> AlCl3 + 6HCl + 3CO2, the coproducts being gaseous.

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