"Indipendent components" actually, which sometimes is a bit tricky because you have to subtract from the number of components the number of equations that link them (eg. take water autoprotolysis: you have three components (H3O+, OH- and H2O) but C=1 because they are linked by the equilibrium constant Kw and the electroneutrality condition (which in this case is equal to the mass conservation: [H3O+]+[OH-]=[H2O])).
Ok, thanks. And the number of equations which link your component(s) is 0 if you have only one component and its phases are involved in phase transition reactions, but nothing else?
Exactly.
You don't happen to know the answer to my original question, do you? (The mathematical calculation of triple point or critical point using G or G° values, or if it's even possible?)
Talking of the triple point I find it quite straightforward: since it's an equilibrium between the three phases the condition you need to apply is (just an example with water triple point, μ is the chemical potential, defined as the derivative of G over the number of moles of the i-th species, which is some sort of "molar" free Gibbs energy):
[tex] \mu_{solid}=\mu_{liquid}=\mu_{gas} [/tex]
Which will have some sort of form like:
[tex] \mu_{solid,\,liquid,\,gas} = \mu_{0;\,solid,\,liquid,\,gas} + RT\ln{a_{solid,\,liquid,\,gas}} [/tex]
that can become awfully complicated (a is the activity of your species, or fugacity for gases) if our substance doesn't really behave as we would like it to, but in the most common case I think you can put the activity equal to 1 for solids and liquids and equal to the pressure for gases. I think it's also necessary to refer all the energies to the same standard state, which I'm not sure if it's the same one (and in general I'm pretty sure that it is not, because there are quite a lot of "standard chemical potentials" depending on the system you're working with) for all the species involved. Whith different triple point you will have to work with different chemical potentials, depending of what equilibrium you're talking about, but I think that is the only condition you need, though I'm not absolutely sure (I'll check if I don't completely forget about this, which is quite possible).
The critical point can be defined as the inflection point of Andrews' isothermal so you only need to put the first and second derivatives of the pressure with respect to volume (obviously you need a state equation for that) equal to zero and you've got it. You can try with van der Waals' equation if you want, after some boring algebra you'll get all the values you need (you can find T
c from the state equation when you're done with the other two conditions).