[Lizzy]

How would you make 100 ml of 3.2 mg/ml isocitrate dehydrogenase (IDH) dissolved in a solution of 20 mM Tris buffer (use a 1.0 M stock of Tris)

This is a practice question for a test so if someone could walk me through it that would be great!

[Borek]

You have to show your attempts at solving the question to receive help. This is a forum policy.

[Lizzy]

Okay so here is how I attempted to solve it.
 3.2 mg/ml of IDH 3.2 * 100= 320 mg of IDH
 20 mM Tris = 0.2 M Tris
 0.2M = xmoles/ 0.1 L x=0.02 moles
 0.02 moles= x/121.1grams x= 2.422 grams
 So I would add 2.422 grams of Tris and 320 mg of IDH to 100ml of H2O?

Is this right? If not can you show me where  I am going wrong?
 

[Babcock_Hall]

You are given a stock solution of Tris buffer in the problem.  Your method, which employs only Tris base, will produce a relatively alkaline solution that may harm the enzyme.