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Topic: H2O Mol Equivalency  (Read 1933 times)

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Offline maleme

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H2O Mol Equivalency
« on: October 06, 2013, 09:03:23 PM »
I'm new to chemistry, doing research, trying to replicate a study, and I don't understand the H2O mol equivalency in the following example.

EXAMPLE: 1.375 g (0.0028 mol) of N3300A was dissolved in 94 mL of dry acetone, 1.5 mol equivalents of water (0.073 mL, 0.0042 mol) was added on top.

I'm trying to substitute the 1.375 g (0.0028 mol) of N3300A with a different monomer, and use the same 1.5 mol equivalents of water (0.073 mL, 0.0042 mol).

How do I calculate the amount of the different monomer I need?

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Offline magician4

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Re: H2O Mol Equivalency
« Reply #1 on: October 06, 2013, 09:17:44 PM »
you need to know the (average) molecular weight M of the replacement, so you can calculate the respective moles n from the mass m : . n = m/M


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