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Equilibrium #1
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Topic: Equilibrium #1 (Read 1544 times)
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Cheistrynoob768
Regular Member
Posts: 22
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Equilibrium #1
«
on:
October 19, 2013, 01:09:57 AM »
Question 5:
http://imgur.com/Wa4BkSk
My work:
http://i.imgur.com/u4KNJWU.jpg
I have a) correct, but I'm stuck on part b... I thought I've done it correctly but I kept getting a wrong answer, the correct answer is [NO2] = 0.56 mol/L and [N2O4] = 0.38 mol/L
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Borek
Mr. pH
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I am known to be occasionally wrong.
Re: Equilibrium #1
«
Reply #1 on:
October 19, 2013, 03:45:12 AM »
In b you don't start with 0.37, you add 0.37 of N
2
O
4
to whatever was already present.
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ChemBuddy
chemical calculators - stoichiometry, pH, concentration, buffer preparation,
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Equilibrium #1