Good afternoon everybody !
Please, apoligize all my mistakes, I'm non an english-spoken person and I just try my best to speak & write it properly.
So.
I'm playing with a benzoic acid, reduced in the corresponding primary alcohol ( 1.05 eq LiAlH4 in THF (Dry, of course), stirring at RT overnight, 99% yield ! *feel happy* )
Since a few days, I try to oxydize it into the aldehyde. Problem, I used some MnO2... A normal one I think.
I did this reaction in DCM, THF, mixture, acetone, refluxed or not... Nothing happened. (5 eq of MnO2)
Finally I get a nice bottle of "activated" MnO2 and my oxydation runned in 45 min ! Awesome isn't it ?
Now, I just simple question. What is the difference between the activated and the non-activated oxydazing agent?
Oxydation state (IV) is the same.
Even if the solid if less brillant it is still a black powder...
Do you have any idea ? Thank !
Bagnar
I get