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Topic: Molybdate ions {equilibria}  (Read 1294 times)

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Offline Big-Daddy

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Molybdate ions {equilibria}
« on: December 11, 2013, 02:57:19 PM »
The following equilibria control the relative concentrations of molybdate and thiomolybdate ions in dilute aqueous solution. A solution initially containing 2.0×10-7 M MoS42- hydrolyzes in a closed system. The H2S product accumulates until equilibrium is reached.

MoS42- + H2O  ::equil:: MoOS32- + H2S
MoOS32- + H2O  ::equil:: MoO2S22- + H2S
MoO2S22- + H2O  ::equil:: MoO3S2- + H2S
MoO3S2- + H2O  ::equil:: MoO42- + H2S

All ions and hydrogen sulphide are aqueous. Write the equilibrium equations that determine the system, noting the possibility that H2S can ionize to HS- and S2- under certain pH conditions. (K values for all of these equilibria are available in tables)

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The equations that confuse me are the mass balances here. Molybdenum mass balance is an obvious summation over all species containing molybdenum, sulphur I don't get: I don't know if I should include the H2S, HS-, S2- in the mass balance that starts from 8*10-7, or not - because H2S is produced as a side-product of the same reaction as produces the molybdate conjugates.
« Last Edit: December 11, 2013, 06:35:56 PM by Arkcon »

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