[greentea11]

1st year should be simple Q..

I have this molecule and some reagents just not sure which part of the molecule it would attack?
Molecule is attached, reagents are NaOH and I2

As it is a carboxylic acid it would be deprotonated in NaOH?

so where would the I2 then attack, is there a name for the mechanism?

My thoughts were that the negative oxygen from the deprotonated in alkai will make the Carbon of the carbonyl group more positive and exposed to attack, but that doesn't seem right with I2?

So would it just attack the double bond

any insight much appreciated

[Rutherford]

http://en.wikipedia.org/wiki/Iodolactonization

[greentea11]

Thank you, that is really useful