Hey everyone,
I was looking through a few questions over a nitration of bromobenzene reaction and had a few questions.
First:
Melting points of pure 2- and 4-bromonitrobenzene are 41 °C and 125 °C, respectively. If purification by crystallization does not provide complete separation of the two products and you end up with a mixture, how would that affect the melting point?
A. the mixture would have the same melting point as the low-melting isomer, i.e. 41 °C
B. the mixture would have the same melting point as the high-melting isomer, i.e. 125 °C
C. the melting point would be either 41 or 125 °C, depending on whichever isomer’s crystal ends up in the melting capillary tube.
D. we would observe a melting point depression
E. we wouldn’t be able to measure the melting point in this case
I was leaning toward D on this one, but wasn't quite sure.
And second:
In the reaction below, what is the yield of 1-bromo-4-nitrobenzene?
http://webcom7.grtxle.com/Chem627/uploads/easpart%202_q3.JPGA. 15%
B. 30%
C. 45%
D. 60%
E. 75%
I had C, but would like to get some other perspectives on this.
Any help at all would be greatly appreciated! Thank you all for your time!