[pinkturtle]

hey folks well i carried out a titration whcih went very well i got concordant results and everything but now i have to write up a report and include calculations which really isnt my strong point

well i found that i tirated 26.3ml of 0.2M HCL to sodiun carbonate
i made my 250ml standard solution with 2.62g of sodium carbonate powder
and now i havet o calulate the concentration of sodium carbonate
am i following the right method ??
0.2x26.37 do i now need to divide it by 1000 or something  

[Albert]

So, correct if I'm wrong, you have 250mL of a solution which contains 2.62g of NaCO3, haven't you?

How many mL of the aforementioned solution did you use for the titration?

[mike]

You need to use the two equations:

n = m/M

&

c = n/v

where: n = number of moles, m = mass, M = molecular weight, c = concentration, and v = volume

so you know the mass of sodium carbonate and its molecular weight therefore you can calculate the number of moles of sodium carbonate.

You then know the number of moles of sodium carbonate and the volume of the solution you made up (250mL) so you can use the second equation to work out the concentration.

Then Albert is correct, you will need to know the volume of the standard that you used for each titration (presuming that you didn't use all 250mL each time).

[pinkturtle]

i used 25ml for each titration thanks for the help guys  

[pinkturtle]

oo dear im not sure if im right i seen to have a really small number can u see where i went wrong ?
26.37ml(titration result)divided by sodium carbonate RFM (106g)
and then
the small decimal answer from above divided by the (250ml) volume  

[Albert]

You dissolved 2.62 g of NaHCO₃ (primary standard) in 250 mL. Determine the total number of moles and calculate how many moles you have in 25 mL.
With the help of the ratio HCl/NaHCO₃, you can easily determine the real molarity of HCl.