[anita1612]

I have this problem in my chem textbook that want me to the pOH of a 0.27 M Sr(OH)₂ ?

I have only done pOH of without it being in solution. What would be the process to answering this question?

[Borek]

I have only done pOH of without it being in solution

pOH is a property of a solution, no idea what you mean.

What is pOH definition?

[cheah10]

Assuming you want to find the pOH of an aqueous Sr(OH)₂ solution.

1st: Find the concentration of OH^- in the solution
[OH^-] = 2[Sr(OH)₂]
        = 2(0.27) M
        = 0.54 M
(the number of OH^- ions released by H₂O molecules are negligible)

2nd: find p[OH^-]
you have to know that
pOH = -log [OH^-]
       = -log (0.54)
       = 0.268 (to 3 significant figures)

and that's it.

[Borek]

Assuming you want to find the pOH of an aqueous Sr(OH)₂ solution.

1st: Find the concentration of OH^- in the solution
[OH^-] = 2[Sr(OH)₂]
        = 2(0.27) M
        = 0.54 M
(the number of OH^- ions released by H₂O molecules are negligible)

2nd: find p[OH^-]
you have to know that
pOH = -log [OH^-]
       = -log (0.54)
       = 0.268 (to 3 significant figures)

and that's it.

Please read the forum rules. Especially the part about not giving final answers.

[cheah10]

I am so sorry about that. I will not do it again.