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Topic: Reaction question  (Read 1941 times)

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Offline sn1sn2e1e2

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Reaction question
« on: March 24, 2014, 12:06:54 AM »
Here is a set of mechanisms..

SO2(aq) + H2O(l)  :rarrow:   HSO3-(aq)  +   H3O+(aq)

2HSO3-(aq)  +    O2(aq)      :rarrow:    S2O7(aq)  +  H2O(l)

S2O7(aq)   +   3H2O(l)      :rarrow:  2SO4 2-(aq)   +   2H3O+(aq)
_______________________________________________________________

HSO3- is an intermediate in this mechanism but it shows up in the overall reaction when you add them up!  Aren't intermediates supposed to be created and destroyed in steps?

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Re: Reaction question
« Reply #1 on: March 24, 2014, 03:54:27 AM »
Show how you add them.

As written they are not all balanced.
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Offline sn1sn2e1e2

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Re: Reaction question
« Reply #2 on: March 24, 2014, 09:36:52 PM »
  You cannot multiply each equation by a coefficient because you do not know the "overall" reaction. They only give you steps. Also, each individual step is already balanced. Therefore, when you add up all the individual steps, the whole reaction is technically "balanced". Couldn't H2O(l) be the intermediate (it's not) since HSO3 - is the intermediate also?


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Re: Reaction question
« Reply #3 on: March 25, 2014, 03:37:57 AM »
you do not know the "overall" reaction.

You do. Overall reaction is oxidation of SO2 to H2SO4 in the presence of water.

Quote
Also, each individual step is already balanced.

No.

What does it mean "balanced reaction"?
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