Apologies if I've put this question is the wrong folder.
I would like to use 5.18 mmol of sodium ethoxide for a reaction
In my lab I have a 21 wt % solution of sodium ethoxide in ethanol. Thus I know that doing a direct calculation of mol= Mass/molecular weight and density= mass/ volume will not give me the correct amount of sodium ethoxide I actually need. I would really like to put this reaction on tomorrow so any help would be much appreciated
MW of NaOEt = 68.05. Density of NaOEt solution =0.868g/ml
Consider one litre of solution. What mass of ethoxide is there in there?
This is the calculation I did. I hope it's correct
I need 5.18 mmol of sodium ethoxide
21wt% solution
21g of sodium ethoxide present in every 100g of solution
MW= 68.05 ( MW of sodium ethoxide) d=0.868 g/ml ( density of solution)
5.18mmol = 0.35g of sodium ethoxide
I need 0.35g of sodium ethoxide
If there Is 21g of sodium ethoxide in every 100g solution.
0.35g will be present in 1.6g of solution
D=m/v
V=1.6g/0.868g/ml
V=1.84ml of sodium ethoxide solution I need