[candysell]

Determine the wavelength, in nanometers, of radiation with of 237kJ/mol energy?

My Answer:438nm

(273kj/mol)(1000J/1kj)(1mol/6.022*10^23)=4.533376615*10^-19 J

λ=hc/E
λ=(6.626*10^-34 J*s)(2.998*10^8 m/s)/(4.533376615*10^-19 J)
=.000000438m--->438nm

Apparently this is wrong so either I did this wrong or my homework is screwed up.

[Borek]

Looks OK to me.

[candysell]

Looks OK to me.

If that's the case, then I can speak to my instructor about it to give me credit for this problem then.

[Borek]

http://www.wolframalpha.com/input/?i=energy+of+a+438nm+photon

Now just multiply by Avogadro's constant.

[Big-Daddy]

237kJ/mol energy?

(273kj/mol)

Perhaps this is why?

[candysell]

237kJ/mol energy?

(273kj/mol)

Perhaps this is why?

Looks like I reversed the numbers.  I don't know how I missed that but thanks for catching that.  I should get it right now.

[Borek]

Sigh, I missed it too.

[candysell]

Sigh, I missed it too.

Thanks.  You helped me confirm that my work was right but we do end up overlooking simple mistakes.  We're humans after all.