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Topic: Equilibrium reactions for multiprotic acids?  (Read 3292 times)

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Offline VoxAure

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Equilibrium reactions for multiprotic acids?
« on: April 09, 2014, 10:58:20 AM »
Hello there!

I'm working to produce a cost-benefit analysis of some chemical treatments. I'm having trouble with my math, and I'd really appreciate some help. Thanks in advance!

Short version:

I'm using an Excel spreadsheet to run equilibrium calculations, and I'm having trouble with acid dissociations.
I'm starting with 12 mg/L of total Phosphorus contained in the water, the vast majority of which is PO4. Because the pH is stable, I'm trying to find out how much of each ion is present.
(Phosphorus is multiprotic and can dissociate into H2PO4(-) HPO4(-2) PO4(-3) so there's a nice big mess here.)
I'm trying to put together formulas in Excel that can find the concentrations of each ion, but for the life of me I can't figure it out. Here's what I have so far:

(H(+)+Δ)(Δ)/(HPO4-Δ)=pKa

Here, Δ represents the reaction unit that dissociates.
Problem is, I'm not really able to solve for Δ here. Because pH is stable, I'm treating H(+) like a constant. My gut tells me this should be quickly solvable and easily modeled with a little bit of Excel, but I'm just not seeing it.

Long version:

This is the reaction for the formation of struvite, a nasty hard salt we don't want clogging up our pipes.
Mg(+2) + NH4(+) + PO4(-3) ::equil:: MgNH4PO4
Current plan is to starve this reaction of phosphate by adding ferric sulfate, which should swap ions for ferric phosphate.
Fe(+3) + PO4(-3) :requil: FePO4(s)
This has a few other added bonuses, like bringing the pH down (struvite becomes more soluble in lower pH) and preventing other nasties like H2S from forming.

Overall, these reactions are occurring at 4°C in biologically active water that's saturated in CO2 and varies from 8-7 in pH. I can give more details if they're needed. (The CO2 part is particularly nasty, because it means any time the CO2 is gassed off, the pH rises and struvite forms. CO2 is gassed in turbulent areas, like the inside of our big expensive pumping stations.)

My goal is to find an ideal dosage amount that could inhibit struvite formation and help dissolve existing struvite in the long term. From there, I can provide cost-per-million-gallons and annual cost estimates.

Offline Borek

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Re: Equilibrium reactions for multiprotic acids?
« Reply #1 on: April 09, 2014, 12:04:45 PM »
Don't waste your time solving it by hand, this calculator:

<a href="http://www.youtube.com/v/ReKHRo7I9x0" target="_blank" rel="noopener noreferrer" class="bbc_link bbc_flash_disabled new_win">http://www.youtube.com/v/ReKHRo7I9x0</a>

does it in no time, and it will allow you to deal with as many acids present in the solution as you want.

http://www.chembuddy.com/?left=Buffer-Maker&right=pH-calculator
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline Big-Daddy

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Re: Equilibrium reactions for multiprotic acids?
« Reply #2 on: April 09, 2014, 09:06:54 PM »
If you want to do the solution yourself, the resource to look up is Robert de Levie's book "Aqueous Acid-base Equilibria and Titrations", Oxford Chemistry Primers. It presents a neat and easily generalized formula for a solution with any number of acids (or bases or salts) that can be quickly transformed to a polynomial in [H+] - and makes no approximations (which is good in a more complicated system like the one it sounds like you're describing, where finding good approximations might get tricky).

Can you state what the components (the starting substances) are more clearly? Then we'd be able to help you directly.

Offline AWK

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