[NamikazeBurst]

I am doing a lab in which I need to use a base with a known concentration (a standard solution that I have to dilute to make a secondary standard) to react with an acid with an unknown concentration. I then have to find the mass of the acid.

I am wondering how I am supposed to find what concentration my secondary standard is supposed to be. I need to use 30-40 mL of it per tablet of ASA (the acid we are using), which are 325 mg each. I guessed 0.1 mol/liter, which can be used, but doesn't follow under 30-40 mL. How do I determine the concentration of secondary standard that will give me 30-40 mL of NaOH (the base) which will dilute 325 mg of ASA dissolved in 10 mL of ethanol?

Summary:
I have to make a standard solution and dilute to make a secondary standard
I must use NaOH (starting as a solid) as the base
I must use 325mg of acetylsalicylic acid as the acid with the unknown concentration
For best results, I should use 30-40 mL of the secondary standard to perform the titration
The ASA is dissolved in 10 mL of ethanol
I am trying to figure out the concentration of the secondary standard of NaOH that will titrate with 30-40 mL

[Hunter2]

Calculate how much moles is your ASA. This correspond to the NaOH. This amount should be in 40 ml. Calculate from your given standard how much you have to dilute.

[NamikazeBurst]

Calculate how much moles is your ASA. This correspond to the NaOH. This amount should be in 40 ml. Calculate from your given standard how much you have to dilute.

We have to make both the standard and the secondary. But I see what you mean, thanks a lot