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Topic: sample praparation/ extraction question Help  (Read 2465 times)

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Offline panchi

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sample praparation/ extraction question Help
« on: June 18, 2014, 10:29:24 PM »
Please help me with this question really badly stuck on it.. Thank you





A weak organic acid (pKa = 4.82) is being studied as a potential broadleaf herbicide. One aspect of the study includes testing for its presence in water samples taken from a run-off of a field.
The acid has a distribution ratio of 62 between water and chloroform at a pH of 3.42.
a.   Using 30.0 mL of chloroform, what fraction of the compound will be extracted from a 50.0 mL field sample at pH = 3.42?
b.   What fraction of the acid in the 50.0 mL sample would be extracted, again at pH 3.42, using three 10.0 mL portions of chloroform?
c.   If the pH of the solution was changed to 6.00, what fraction would be extracted using 30.0 mL of chloroform with a 50.0 mL field sample?
d.   Qualitatively, predict what effect a lower pH would have on the extraction.

Offline Hunter2

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Re: sample praparation/ extraction question Help
« Reply #1 on: June 19, 2014, 01:00:43 AM »
Check Nernst Distribution law.

http://en.wikipedia.org/wiki/Distribution_law

Offline Borek

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Re: sample praparation/ extraction question Help
« Reply #2 on: June 19, 2014, 02:45:51 AM »
You have to show your attempts at solving the question to receive help. This is a forum policy.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline panchi

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Re: sample praparation/ extraction question Help
« Reply #3 on: June 19, 2014, 06:28:31 PM »
ka=10^-4.82 = 1.5136*10^-5

ph=3.42

q = 50/(30+62) = 0.5435

Offline sjb

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Re: sample praparation/ extraction question Help
« Reply #4 on: June 20, 2014, 01:49:39 AM »
ka=10^-4.82 = 1.5136*10^-5

ph=3.42

q = 50/(30+62) = 0.5435

and 6 x 9 = 42, if you believe some texts. What do these calculations mean? Whilst I can see that lines 1 and 2 have possible relevance, not sure about the last one.

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