[kosho]

The problem is:

Drying time in the area of constant drying speed is 2 hours if drying with air temperature 60 degrees of celsius. For this air the humidity at 20 degrees of celsius is 40%. What would be the drying time from the same starting to final point if the air temperature would be 90 degrees of celsius? How much will the drying speed change, if linear speed of air above surface is decreased on half of its value?

Any idea how to solve it? If air has 40 percent humidity at 20 degrees celsius, what is its humidity at 60 degrees celsius and what at 90 degrees celsius?

[billnotgatez]

@kosho
Did you read the forum rules before posting?

[kosho]

I have read the rules.

I tried to solve this using the equation for the area of constant drying speed: t = K (X2 - X1), where K is Ls/(ARc), Ls is mass of dry material [kg], R is speed of drying [kg of water / (h m^2)], A area of drying [m^2]

the problem is that I can't figure it out how to determine X2 and X1 from the data given. the key is to determine X at 60°C and X at 90°C.

As for the second part of the problem, I have no idea at all how to try to solve it

[kosho]

Is this appropriate approach or not?