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Topic: New to physical chemistry! Need *delete me*  (Read 2458 times)

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Offline diamie24

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New to physical chemistry! Need *delete me*
« on: October 23, 2014, 06:42:55 AM »
For a second order reaction, I am trying to find [At].  The initial concentration [Ao] is 4.20 M.  If the initial concentration drops 20% of it's value, do I just take 20% of the initial concentration?
« Last Edit: October 23, 2014, 07:39:25 AM by diamie24 »
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Offline Hunter2

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Re: New to physical chemistry! Need *delete me*
« Reply #1 on: October 23, 2014, 07:05:42 AM »
Quote from: diamie24 on October 23, 2014, 06:42:55 AM
The rate constant for a second order reaction is 0.650 M-1min-1. With an initial concentration of reactant of 4.20 M, how many minutes does it take for the concentration to drop to 20% of its initial concentration?

1/[At] =kt + 1/[Ao]

I am having trouble finding [Ao].  Do i take 20% of 4.20M and subtract that value from the initial concentration?

4.20 x 0.20 =0.84
4.20-0.84=3.36M = [Ao] ??

No A0 is the 4.20 M and and A(t) is the 20% of A0
« Last Edit: October 23, 2014, 09:05:34 AM by Borek »
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Offline diamie24

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Re: New to physical chemistry! Need *delete me*
« Reply #2 on: October 23, 2014, 07:21:35 AM »
0.84?
« Last Edit: October 23, 2014, 07:39:54 AM by diamie24 »
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Offline Hunter2

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Re: New to physical chemistry! Need *delete me*
« Reply #3 on: October 23, 2014, 07:27:38 AM »
And now calculate t
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