November 27, 2024, 03:36:53 PM
Forum Rules: Read This Before Posting


« previous next »
Pages: [1]   Go Down

Topic: New to physical chemistry! Need *delete me*  (Read 2457 times)

0 Members and 2 Guests are viewing this topic.

Offline diamie24

  • New Member
  • **
  • Posts: 5
  • Mole Snacks: +0/-1
New to physical chemistry! Need *delete me*
« on: October 23, 2014, 06:42:55 AM »
For a second order reaction, I am trying to find [At].  The initial concentration [Ao] is 4.20 M.  If the initial concentration drops 20% of it's value, do I just take 20% of the initial concentration?
« Last Edit: October 23, 2014, 07:39:25 AM by diamie24 »
Logged

Offline Hunter2

  • Sr. Member
  • *****
  • Posts: 2298
  • Mole Snacks: +189/-50
  • Gender: Male
  • Vena Lausa moris pax drux bis totis
Re: New to physical chemistry! Need *delete me*
« Reply #1 on: October 23, 2014, 07:05:42 AM »
Quote from: diamie24 on October 23, 2014, 06:42:55 AM
The rate constant for a second order reaction is 0.650 M-1min-1. With an initial concentration of reactant of 4.20 M, how many minutes does it take for the concentration to drop to 20% of its initial concentration?

1/[At] =kt + 1/[Ao]

I am having trouble finding [Ao].  Do i take 20% of 4.20M and subtract that value from the initial concentration?

4.20 x 0.20 =0.84
4.20-0.84=3.36M = [Ao] ??

No A0 is the 4.20 M and and A(t) is the 20% of A0
« Last Edit: October 23, 2014, 09:05:34 AM by Borek »
Logged

Offline diamie24

  • New Member
  • **
  • Posts: 5
  • Mole Snacks: +0/-1
Re: New to physical chemistry! Need *delete me*
« Reply #2 on: October 23, 2014, 07:21:35 AM »
0.84?
« Last Edit: October 23, 2014, 07:39:54 AM by diamie24 »
Logged

Offline Hunter2

  • Sr. Member
  • *****
  • Posts: 2298
  • Mole Snacks: +189/-50
  • Gender: Male
  • Vena Lausa moris pax drux bis totis
Re: New to physical chemistry! Need *delete me*
« Reply #3 on: October 23, 2014, 07:27:38 AM »
And now calculate t
Logged
Pages: [1]   Go Up
« previous next »
Sponsored Links