I calculated NAD moles from the beer lambert law, using vmax value.
Also, i was giving initial concentration of nad in the solution, and it came out to be a larger number than from the first calculation. So it means that not all of NAD was used. So the calculation via beer law gave me how much of NAD was used...
the question is : in the case of vmax, connvert your results to umolf os nad used/min/mg...
the only results i have are vmax and km.
I think I just do not understnad what they want from me in this part...
I calculated the mols of NAD used, so what's next?? it can't be it, there are 10 marks for this question!
thank you for any help and clues!