December 29, 2024, 06:20:38 AM
Forum Rules: Read This Before Posting


Topic: adiabatic isobaric free expansion  (Read 2513 times)

0 Members and 1 Guest are viewing this topic.

Offline tvtokyo

  • Regular Member
  • ***
  • Posts: 18
  • Mole Snacks: +0/-2
adiabatic isobaric free expansion
« on: November 10, 2014, 10:41:35 PM »
I just have a question to pounder
Why cant we have an "adiabatic isobaric free expansion". I mean what are the factors and points that we have to exaplain.
adiabatic = q=0   and isobaric means constant pressure while free expansion means work done is 0. How do i link them?
Thanks.

Offline mjc123

  • Chemist
  • Sr. Member
  • *
  • Posts: 2074
  • Mole Snacks: +302/-12
Re: adiabatic isobaric free expansion
« Reply #1 on: November 11, 2014, 05:38:14 AM »
You can't have an isobaric expansion, unless you raise the temperature so V2/T2 = V1/T1. That can't be adiabatic because you need the energy to raise the temperature.

Offline mjc123

  • Chemist
  • Sr. Member
  • *
  • Posts: 2074
  • Mole Snacks: +302/-12
Re: adiabatic isobaric free expansion
« Reply #2 on: November 11, 2014, 08:49:23 AM »
It may be clearer on a graph. As you can see, an isobaric expansion must involve a temperature rise. For an adiabatic expansion, however, the work must come from the internal energy, so temperature falls. For an equilibrium adiabatic expansion, the line follows PVγ = constant. If Pext < Pgas, the work done is less and the temperature drop is less; in the limit of zero work the line will coincide with the isotherm. But I hope you can see it will never coincide with the isobar.

Sponsored Links