1 part per million in the water. 1000 ppm in toothpaste (average).
So H
2O molecular weight = (2+16 = 18) grams per mol.
18/6.02*10
23 = 2.99*10
-23 grams per molecule.
1,000,000 * 2.99*10
-23 = 2.99*(10
-17) grams of water per Fluoride ion.
The average man needs around 2800mL water per day, and a mL of pure water weighs 1g.
2800/(2.99*10
-17) = 9.36*10
19 fluoride ions consumed per day.
Fluoride ion mass = 19, so:
19/(6.02*10
23)*9.36*10
19 = 2.954*10
-3 grams of Fluoride per day. (can someone check my calculations please - I'm pretty new to chemistry).
2.9mg doesn't seem like much I guess. The recommended dosage is listed here
http://www.nlm.nih.gov/medlineplus/ency/article/002420.htm as being 3-4mg a day for an adult human.
I've read that fluorides bioaccumulate, mainly due to the F ion's proclivity for binding to the calcium in bones. Also, it might be worth noting that in countries where drinking water is fluoridated there is a feedback mechanism at play. Not only do you get it in your water, you get it through the plants that are watered with it, the food products using water in processing, the beverages that use water as an additive (like Coke and reconstituted orange juice).
There are many, many, sources that claim fluoride is a poison - it used to be used in rat poison, for instance, and rats are used in medical research because their systems often behave similarly to ours. The Nazis apparently used it in their concentration camps as a means of making people more compliant and less likely to cause trouble. It's hard to know whose information to trust really.