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Topic: uni - chemistry {red-ox}  (Read 2372 times)

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Offline shawen

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uni - chemistry {red-ox}
« on: December 06, 2014, 07:30:42 PM »
Element X is a toxic semi-metal. It is often found as an impurity in charcoal and in mine tailings. A sample of element X is heated in excess oxygen to produce the oxide X203, which is then dissolved in water and analyzed by titration with permanganate according to this reaction

H2O(i) + X203(s) + MnO4(aq) Right arrow Mn^2+ (aq) +H3XO3 (aq) (acidic) Give the full balanced reaction:

b) Which element is oxidized, and which element is reduced? Element oxidized: Element reduced:

c) The titration used 10.7 mL of 0.100 M MnO4 solution. Calculate the number of moles of element X present in 0.200 g.

d) Based on the above, calculate the molar mass of Element X and give the name or symbol of the element.
Molar mass: g/mol           and                       Element X is :

i tried but i am not getting the answer
show me the answer step by step please
please help me and i have exam on monday
please

thanks alot :)

*MOD Edit - Add useful title*
« Last Edit: December 06, 2014, 08:16:42 PM by Arkcon »

Offline Arkcon

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Re: uni - chemistry {red-ox}
« Reply #1 on: December 06, 2014, 08:23:18 PM »
Welcome the the chemicalforums, shawen:.  Please trouble yourself to read the Forum Rules{click}, we like to see some effort from posters, on this forum.  You can begin by determining the oxidation  states of the one reactant that you do know.  Is it oxidized or reduced?
Hey, I'm not judging.  I just like to shoot straight.  I'm a man of science.

Offline shawen

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Re: uni - chemistry {red-ox}
« Reply #2 on: December 06, 2014, 08:31:07 PM »
i did some work
i think it Mn is oxidized
and x is reduced


Offline Borek

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Re: uni - chemistry {red-ox}
« Reply #3 on: December 07, 2014, 03:36:30 AM »
i think it Mn is oxidized

Permanganate (MnO4-) is a strong oxidizer, and it always gets reduced.

However, in this case there is no other redox reaction - X2O3 just reacts with water to produce H3XO3. Are you sure you have copied the reaction equation correctly?
« Last Edit: December 07, 2014, 03:48:13 AM by Borek »
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