January 15, 2025, 05:56:28 PM
Forum Rules: Read This Before Posting


Topic: Question about thermochemical equations  (Read 1766 times)

0 Members and 1 Guest are viewing this topic.

Offline John623

  • Regular Member
  • ***
  • Posts: 16
  • Mole Snacks: +0/-0
Question about thermochemical equations
« on: February 01, 2015, 10:09:49 PM »
Let's say I have the following equation:

CH4(g) + 2O2(g)  :rarrow: CO2(g) +2H2O(l)

I know that if I want to turn it into a thermochemical equation I need to add ΔH but I'm not sure when you add all the other details such as if it's combustion and if it was done at standard conditions. For example.

I assume this is the thermochemical equation:
CH4(g) + 2O2(g)  :rarrow: CO2(g) +2H2O(l) ΔH = -890kJ/mol

Is this still a thermochemical equation now i've added some extra details?
CH4(g) + 2O2(g)  :rarrow: CO2(g) +2H2O(l) ΔH°c = -890kJ/mol

What type of equation do I here when I put in the details of what I burned? I'm no sure if I should be doing this or not.
CH4(g) + 2O2(g)  :rarrow: CO2(g) +2H2O(l) ΔH°c CH4(g) = -890kJ/mol

Does this type of equation have a name?
 ΔH°c CH4(g) = -890kJ/mol

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27895
  • Mole Snacks: +1816/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Question about thermochemical equations
« Reply #1 on: February 02, 2015, 03:13:34 AM »
I feel like you are making similar mistake as it was with the cell notation - you assume there is a highly precise definition of how the "thermochemical equation" should be written. I am not aware of one.

Technically reaction of hydrocarbon with oxygen (one the goes to the end and produces H2O and CO2) is combustion, you don't have to name it as such. Zero in ΔH° means it is given for STP.

CH4(g) + 2O2(g)  :rarrow: CO2(g) +2H2O(l) ΔH = -890kJ/mol

Combustion, conditions not clear.

Quote
CH4(g) + 2O2(g)  :rarrow: CO2(g) +2H2O(l) ΔH°c = -890kJ/mol

Assuming c means combustion, this information is duplicated - it is obvious you are talking about combustion from the reaction equation.

Quote
CH4(g) + 2O2(g)  :rarrow: CO2(g) +2H2O(l) ΔH°c CH4(g) = -890kJ/mol

Again, plenty of information repeated.

Quote
ΔH°c CH4(g) = -890kJ/mol

This is quite sufficient - while it doesn't give an exact reaction, there is only one combustion reaction for CH4, and every chemist knows what it is.

There is one problem left - sometimes when you balance combustion reaction, hydrocarbon will require a coeffcient of 2

2C2H2 + 5O2 :rarrow: 4CO2 + 2H2O

Then, if the enthalpy is listed as ΔH°c it can be slightly ambiguous - is it per mole of the hydrocarbon, or is it "per mole of reaction as written"? It is good to clarify the situation in such cases but explicitly explaining what you mean.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Sponsored Links