Since the tube is thin, I consider the octagon never stands perfectly flat in the wind, so the rear side gets the full wind force as well.
For the inclined sides, I take the same drag (=component force parallel to the wind) as a cylinder of the same area as seen from the wind's direction. That overestimates the drag a bit.
Then the drag is the same as a cylinder of 2*26m length and 63.5mm diameter. At Re~105 the drag coefficient is just above 1, so the drag is 1000N.
Drag predictions are rather inaccurate, so take margins for real. In addition, objects often vibrate in the wind, and cylinders more so, which amplifies the mechanical loads.