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Topic: [Cu(NH₃)₄]²⁺ or [Cu(NH₃)₄(H₂O)₂]²⁺ ?  (Read 5105 times)

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Offline strugglingstudent

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[Cu(NH₃)₄]²⁺ or [Cu(NH₃)₄(H₂O)₂]²⁺ ?
« on: February 24, 2015, 03:49:22 PM »
If I am making a complex ion with ammonia solution and copper (II) hydroxide precipitate, would the complex ion be [Cu(NH₃)₄]²⁺ or [Cu(NH₃)₄(H₂O)₂]²⁺ ?

[Cu(NH₃)₄]²⁺ would have a square planar shape and have bond angles of 90ᵒ
but
[Cu(NH₃)₄(H₂O)₂]²⁺ would have an octahedral shape and have bond angles of 109ᵒ

which one am I making? Any help would be very useful. Thank you :)
« Last Edit: February 24, 2015, 04:05:56 PM by strugglingstudent »
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Offline sjb

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Re: [Cu(NH₃)₄]²⁺ or [Cu(NH₃)₄(H₂O)₂]²⁺ ?
« Reply #1 on: February 24, 2015, 05:00:31 PM »
Quote from: strugglingstudent on February 24, 2015, 03:49:22 PM
If I am making a complex ion with ammonia solution and copper (II) hydroxide precipitate, would the complex ion be [Cu(NH₃)₄]²⁺ or [Cu(NH₃)₄(H₂O)₂]²⁺ ?

[Cu(NH₃)₄]²⁺ would have a square planar shape and have bond angles of 90ᵒ
but
[Cu(NH₃)₄(H₂O)₂]²⁺ would have an octahedral shape and have bond angles of 109ᵒ

which one am I making? Any help would be very useful. Thank you :)

How do you propose octahedral shape and bond angles of 109ᵒ
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Offline mjc123

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Re: [Cu(NH₃)₄]²⁺ or [Cu(NH₃)₄(H₂O)₂]²⁺ ?
« Reply #2 on: February 25, 2015, 05:53:13 AM »
The complex ion has a charge of 2+, not 2-.
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