some additional information you might find usefull:
What I did afterwards was to use the formula Ksp = [Ca2+][OH-]^2 to determine the product solubility.
asides from the what Borek already mentioned, I'd like to point out that this approach will lead to questionable results (as you will see when you compare the Ksp gained hereby to the one known to literature , Ksp 5.02 * 10
-6 mol³/L³ )
reason is , that most (sic !) of the calcium in a saturated solution of calciumhydroxide is
not present as "Ca
2+" , i.e. [Ca(H
2O)
6]
2+ instead, it "hides" in other complexes ( [Ca(H
2O)
5(OH)]
+ , [Ca(H
2O)
4(OH)
2] , to name them), as calciumhydroxide is not a strong base (i.e. completely dissociated) under these conditions*
),
and those complexes are not being accounted for in the Ksp known to literature! (
only the "real" [Ca(H
2O)
6]
2+ is)

that's one of the major reasons , why your result will differ from the Ksp known to literature
regards
Ingo
*
)the base constants of Ca(OH)
2 are pKb 1 = 1,37 and pKb2 = 2,43 , respectively
... and this will lead to kind of buffers at pH ~ 12.75 (that's what a saturated calciumhydroxide solution usually shows) , which then will cause the problems in recalculation mentioned above