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Topic: Find the moment of inertia and the energy (in kJ/mol) of a nitrogen molecule N2  (Read 18297 times)

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camariela

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Hello,
I'm confused about the formulas to use and combine to find the moment of inertia and the energy (in kJ/mol) of a nitrogen molecule (N2) in its first excited rotational state.

Thanks
camariela
« Last Edit: April 13, 2006, 12:38:29 AM by Mitch »

Offline Mitch

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Re: Moment of Inertia
« Reply #1 on: April 13, 2006, 12:35:48 AM »
What's the equation for moment of inertia?
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camariela

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I = mr^2

i have the mass, but what do i use for r?

Offline Mitch

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The radius of a Nitrogen atom I suppose.
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I would rather go for half a triple bond length (or even better for half a N2 length). Atomic radius is for free atom and is of no use here.
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Offline Mitch

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I would rather go for half a triple bond length

I was thinking of rotation down the central axis. Which is the more meaningful?
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Not sure what you mean, but only A variant has any meaning. In B both masses (both nuclei to be precise) lie on the rotation axis and moment of inertia of the particle is zero.
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Yeah, for the B base the only off-axis masses are the electrons and the fact that the nucleus isn't really a point.
Both of these would be some effort to calculcate.

For the A case, the N nuclei masses dominate the calculation, so you can ignore the above complications.

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Both of these would be some effort to calculcate.

Do you have any idea if anybody ever tried to? AFAIR (but QM and spectroscopy were never my favourite subjects) only A was always taken into account. Assuming electron cloud have some moment of inertia changes in rotational energy could be observable in spectroscopy (although probably for wavelengths comparable with astronomical unit :) ).
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Offline pantone159

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Do you have any idea if anybody ever tried to?

Don't know.

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To calculate the moment of inertia of a diatomic molecule, one must use the formula I = mR2, where m is the reduced mass of the molecule (m1m2/m1+m2) and R is the bond length.

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You mean half the bond length?
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Offline plu

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Actually, no.  R is simply the whole bond length.

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Good to know. :)
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Actually, no.  R is simply the whole bond length.

Using the 'reduced mass' takes care of these halves, as well as counting both nuclei.

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