Hi
I would like to ask you how to synthesize bismuth phosphate - BiPO4.
Since it's a salt, I wander if simple salt obtaining methods will work. Like:
Metal + acid = salt + H so Bi + H3PO4 = BiPO4 + 3H
No.
Look up the position of bismuth in electrochemical series...
oops, electrochemical series as a standard misses a lot of elements. Who presents the full electrochemical series?
Anyway, from
http://en.wikipedia.org/wiki/Standard_electrode_potential_%28data_page%29Ge
4+ + 4 e
− is in equilibrium with Ge(s) +0.12
SbO
+ + 2 H
+ + 3 e
− is in equilibrium with Sb(s) + H
2O +0.20
H
3AsO
3(aq) + 3 H
+ + 3 e
− is in equilibrium with As(s) + 3 H
2O +0.24
Re
3+ + 3 e
− is in equilibrium with Re(s) +0.300
Bi
3+ + 3 e
− is in equilibrium with Bi(s) +0.308
Cu
2+ + 2 e
− is in equilibrium with Cu(s) +0.337
So: Bi, like Cu, Re, As, Sb and Ge, will not react with nonoxidizing acids like HCl or H
3PO
4or
Metal oxide + acid = salt + H20 so Bi2O3 + 2H3PO4 = 2BiPO4 + 3H20
Would 75% phosphoric acid work?
Or does it need to be done in another way?
Could be.
Phosphoric acid is a medium strength AND tribasic acid and Bi
3+ is a strongly hydrolyzed cation. Depending on the details of the solubilities of various Bi solid salts in concentrated phosphoric acid, you might end up with (BiO)
3PO
4, or Bi(H
2PO
4)
3, or something else again...