[Fliss247]

I'm seriously stuck with this question:

In a titration a student pipettes 25.00 mL of nitric acid into his flask. It takes 20.63 mL of 0.346 M potassium hydroxide to reach the equivalence point. Calculate the concentration of the nitric acid in mol/L?

Could you please explain step by step how to work this out?

Need to know how to do it quiet urgently!

Thank you

[sjb]

I'm seriously stuck with this question:

In a titration a student pipettes 25.00 mL of nitric acid into his flask. It takes 20.63 mL of 0.346 M potassium hydroxide to reach the equivalence point. Calculate the concentration of the nitric acid in mol/L?

Could you please explain step by step how to work this out?

Need to know how to do it quiet urgently!

Thank you

What is the balanced equation for the reaction that takes place?

[Borek]

Please read the forum rules.

You have to show your attempts at solving the question to receive help. This is a forum policy.

http://www.titrations.info/titration-calculation

[Fliss247]

The balanced equation would be:

HNO3 + KOH -> KNO3 + H20??

Therefore thats a one to one reaction so does that mean that the number of moles of KNO3 =  number of moles HNO3?

Therefore:

KNO3 Concentration = c = 0.346 M because M means molarity right?


But then im confused because i have tried multiple ways but nothing is correct

[Hunter2]

No.

Calculate the moles of the KOH . These have to be equal to HNO₃. Then combine this to the given volume of the acid.