[abrahamsaynes]

 I need help solving this problems, can you show me calculations.

How many litres of CO2 will approximately be evolved in the reaction of 18 g of
potassium hydrogen carbonate with 65 g of 10 % sulphuric acid? 
A)   1,        B)   2,        C)   3,        D)   4,        E)   5.
Answer c)

What must be the minimum concentration (% by mass) of 1 kg of a potassium hydroxide
solution for a complete neutralisation of 3.57 moles of nitric acid? 
A)   5 %,   B)   10 %,   C)   15 %,   D)   20 %,   E)   25 %.
Answer d)

 How many litres of air are approximately required for complete combustion of 1 litre of
ammonia? 
A)   1,        B)   2,        C)   3,        D)   4,        E)   5.
Answer D)

[sjb]

Step 1, what is the balanced equation?

[abrahamsaynes]

*MOD Edit -- Quote of a quote of the OP removed*

H2SO4 + 2KHCO3 ---> K2SO4 + 2CO2 + 2H2O

[sjb]

MOD Edit -- Quote of a quote of the OP removed*
w
H₂SO₄ + 2KHCO3  K₂SO₄ + 2CO₂ + 2H₂O

OK, so how many moles of potassium hydrogen carbonate is there? How many moles of acid? Which is the limiting reagent?

[abrahamsaynes]

MOD Edit -- Quote of a quote of the OP removed*
w
H₂SO₄ + 2KHCO3  K₂SO₄ + 2CO₂ + 2H₂O

OK, so how many moles of potassium hydrogen carbonate is there? How many moles of acid? Which is the limiting reagent?

i dont know thats all what the problem says.

[Arkcon]

i dont know thats all what the problem says.

Please avoid excessive quoting.  There's no need to quote your own post, along with someone else's post, when you respond again.  The forum is a thread, we already have your old post.  Did you notice, I only quoted you latest post?  Do that next time please.

I've already told you once before, here: http://www.chemicalforums.com/index.php?topic=80943.msg294731#msg294731  This is a learning forum, we will give you hints, and expect to see some work, using those hints.  When sjb: wrote:

OK, so how many moles of potassium hydrogen carbonate is there? How many moles of acid? Which is the limiting reagent?

He meant for you to calculate moles, based on the information you have been given.  Can you do this?  If you can, do that in your next post.  With posting a:

Hahahahaha yeah

Like you did here:  http://www.chemicalforums.com/index.php?topic=80943.msg294821#msg294821  That's not a useful use of our forum space.