Given: A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 ∘C. The initial concentrations of Pb2+ and Cu2+ are 5.10×10−2 M and 1.60 M , respectively. Initial cell potential is 0.51V
Question: What are the concentrations of Pb2+ and Cu2+ when the cell potential falls to 0.360 V ?
Enter your answers numerically separated by a comma. Express your answer using two significant figures.
I checked my calculations and my answer should be correct. I got [Pb2+], [Cu2+] = 1.6, 0.04. But Masteringchemistry.com kept saying that my answer is wrong! I don't get it, please help.